(2x-7)(x^2-9)=0

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Solution for (2x-7)(x^2-9)=0 equation: 


Simplifying
(2x + -7)(x2 + -9) = 0

Reorder the terms:
(-7 + 2x)(x2 + -9) = 0

Reorder the terms:
(-7 + 2x)(-9 + x2) = 0

Multiply (-7 + 2x) * (-9 + x2)
(-7(-9 + x2) + 2x * (-9 + x2)) = 0
((-9 * -7 + x2 * -7) + 2x * (-9 + x2)) = 0
((63 + -7x2) + 2x * (-9 + x2)) = 0
(63 + -7x2 + (-9 * 2x + x2 * 2x)) = 0
(63 + -7x2 + (-18x + 2x3)) = 0

Reorder the terms:
(63 + -18x + -7x2 + 2x3) = 0
(63 + -18x + -7x2 + 2x3) = 0

Solving
63 + -18x + -7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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